Quick Guide of Smart Courseclose
The Etoosindia SD card learning is very easy and simple.
A few simple steps, you can learning to anytime, anywhere.
※ Etoosindia learning of SD card is only available for Samsung Tablet.
- Mount SD card: tInsert SD card on the Samsung tablet.
- Connect internet: Connect to the Internet using WiFi or 3G.
- Run application: Run the Shelf Reader Application.
- Create account: Click New user to create a new account.
- Login & Activation: After login, select the desired course.
(Activation is the first one you enter only once.)
Important dates of examinations (2017)
13 Apr 2017
- JEE MAIN EXAM DATE– 2nd April 32017
- JEE MAIN RESULT DATE- 27th April 2017
- JEE ADVANCED DATE – 21st May 2017
- JEE ADVANCED RESULT DATE - 11th June, 2017
- NEET EXAM DATE- 7 May 2017
- NEET RESULT DATE- 8 June 2017
- CBSE CLASS 10th EXAM DATE- 9th March- 10th April
- CBSE CLASS 12th EXAM DATE- 9th March- 29th April
- CBSE CLASS 10th RESULT- 30th May 2017
- CBSE CLASS 12th RESULT- 21st May 2017
ETOOSINDIA JEE MAIN 2017
03 Apr 2017
Dear all aspirants, Etoosindia provides you video solution for JEE MAIN 2017 held on 2nd April 2017 (Sunday). Not only this time, periodically Etoosindia providing you video solutions for competitive exams which helps you not only too analyse your result but also for the new aspirants to understand the depth and importance of examination. Etoosindia provides you video solutions given by Kota's top most and experinced faculties.
For more detials go to : http://www.etoosindia.com/examinfo/jee/videoSolution.do
ETOOSINDIA new offer launched
01 Apr 2017
Etoosindia, known to offer JEE, AIPMT and CBSE online coaching at the most affordable cost, is here with yet another discount offer. This all new offer launched under the name, BY MORE,MORE CHANCE on all the JEE, CBSE and AIPMT courses. For more details, Go to: http://www.etoosindia.com/promotion/main.do
JEE Main Exams 2017
31 Mar 2017
JEE Main 2017 is scheduled for the 2nd of April (pen and paper based) and 8th and 9th April (computer-based) this year. Like each year thousands of IIT aspirants are expected to appearing for this competitive exam. Top 220,000 among those who qualify will be eligible to sit for JEE Advanced 2017
Most of the students begin preparing for the exam when they are still in their 11th grade and dedicate two complete years for its preparation. The competition is tough and a lot of stress and nervousness builds up before the exam. The speculation about the performance after appearing for the exam creates even more anxiety among the students. In order to end this speculation, institutes such as Etoosindia will release JEE Main 2017 answer key within two-three hours of the exam as is done every year.
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Q. a train of mass pie kg is moving on the circular track of radius r ,the length of a train is half the perimeter of circular track and its velocity is 2m/s. then find :linear momemtum of the particle???
"MY APPROACH:calculate dw ,by dw=f.ds then integrate both sides find w? then use,
net work done =change in k.e.
as we know k.e.=p^2/2m
2mw^0.5=p=linear momemtum of particle .
sir bs integrate kARNE MAI PROBLEM HO RHI H....
PLS TELL MERI APPROACH CORECT HAI KI NAHI????????????"""""JEE, Physics, Centre of Mass
Please to be answer only by faculties..
Que1-Sir agar two positive charge rakhe huye hai aur unke line joining pe ek aur positive charge rakha hua hai aur usko perpendicular to the line joining X distance move karaya ÂÂ jataÂÂ hai aur wo charge SHM perform karne lagta hai to hum uska time period nikalne ke liye uspe NET FORCE nikalte hai to hum us NET FORCE Â MEIN mg downward ko kyun include nahi karte hai.....JEE, Physics, Electrostatics
Que. Two wire of Equal length and cross section area is shown in the given diagram.These young modulous are Y1 and Y2 then total young modulous will be...
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